March 11, 2010 at March 11, 2010 · Filed under enart.nnxj.comedit
Is it possible to use the value of a variable as the first parameter
to a list() command?
I'm trying the following with no success - I did have the variables
hardcoded in the list command - but I'd like to be able to make this
variable too if possible - can it be done simply? The only way I can
think of is creating the php script on the fly and running that, which
I'd rather not do?
Vladimir
I mailed GA support today saying what a great job you'd done.
Thanks very much for your help - no doubt I may have other things to
ask you in future....You can use the eval() function to execute code that was constructed dynamically.
http://www.php.net/manual/en/function.eval.php
VladimirVladimir,
Perfect. Thank you very much.
That had me stumped all afternoon. Are you a researcher - if so, post
this as your answer.For example this should do the trick:
$temp = '$title,
$first_name,
$surname,
$address_line1,
$address_line2,
$address_line3,
$address_line4,
$address_line5,
$postcode';
eval('list('.$temp.') = explode($file_delimiter,$buffer);');
VladimirI'm not a researcher. If you want to help me become one, you can
e-mail answers-support@google.com saying that vladimir-ga helped you
and you think he would make a good researcher. :)
Vladimir#If you have any other info about this subject , Please add it free.# |
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